Question

4х (х в квадрате) = 3, знайти х і у: 1) 6ху (х в квадрате).2) 4ху (х в четвертій степені, у в квадраті). 3) -3ху (х в 6 степені, у в 3й степені)

Answer 1

Условие 4х^2у=3
Х^2у=3/4
1) 6х^2у=6*(х^2у)=6×(3/4)=4.5
2)4х^4у^2=4*(х^2у*х^2у)=4(3/4*3/4)=2.25
3) -3х^6у^3=-3*(х^2у*х^2у*х^2у)=-3(х^2у)^3=-3*(3/4)^3=-63/64

Answer 2

To find the values of x and y in the given equations, we'll solve each equation step-by-step:

1. 4x(x^2) = 3 Rewrite the equation as a cubic equation: 4x^3 = 3

Now, solve for x: x^3 = 3/4 x = (3/4)^(1/3)

2. 6xy(x^2) We have the value of x from the previous equation. Let's assume this equation equals 0, so we can find the value of y: 6xy(x^2) = 0

Since x^2 cannot be zero (as x^(1/3) is non-zero), we set y = 0.

3. -3xy(x^6)(y^3) We already know y = 0, so the entire expression becomes 0.

To summarize:

1. x = (3/4)^(1/3) and y can be any real number.
2. x = (3/4)^(1/3) and y = 0.
3. x = (3/4)^(1/3) and y = 0.