Question

Сократите дробь 8+b³/4-b²

Answer 1

Выйдет правильно в примере

Answer 2

Це буде правельно просто =

Answer 3

To simplify the fraction (8 + b³)/(4 - b²), you can factor the numerator and denominator if possible. In this case, the numerator is a sum of cubes, and the denominator is a difference of squares. The factorization can be done as follows:

1. Factor the numerator (sum of cubes): a³ + b³ = (a + b)(a² - ab + b²)

So, with "a" being 2 and "b" being "b," the numerator becomes: 8 + b³ = (2 + b)(4 - 2b + b²)

2. Factor the denominator (difference of squares): a² - b² = (a + b)(a - b)

So, with "a" being 2 and "b" being "b," the denominator becomes: 4 - b² = (2 + b)(2 - b)

Now, the fraction can be simplified as follows:

(8 + b³)/(4 - b²) = [(2 + b)(4 - 2b + b²)] / [(2 + b)(2 - b)]

Next, we can cancel out the common factor (2 + b) in the numerator and denominator:

(8 + b³)/(4 - b²) = (4 - 2b + b²) / (2 - b)

So, the simplified fraction is (4 - 2b + b²) / (2 - b).