Question

15tg(arccos3/корень34)

Answer 1

$\tt 15tg\left(arccos \left(\dfrac{3}{\sqrt{34}}\right)\right)=15 \cdot \dfrac{\sqrt{1-\left(\dfrac{3}{\sqrt{34}\right)^2}}}{\dfrac{3}{\sqrt{34}}}=15 \cdot \dfrac{5}{\sqrt{34}} \cdot \dfrac{\sqrt{34}}{3} = \bf 25$

Answer 2

It appears that there is a mix of different mathematical notations and some characters that are not recognizable. However, I will do my best to interpret the expression and provide you with an answer.

I assume the expression is: 15 * tg(arccos(3/√34))

In this case:

• arccos represents the inverse cosine function (also known as the arc cosine or cos^-1).
• tg represents the tangent function (also known as tan).

To simplify the expression, let's first calculate the values inside the trigonometric functions:

arccos(3/√34): arccos(3/√34) ≈ 72.7919 degrees (rounded to four decimal places)

Now, let's find the value of the tangent function for the angle 72.7919 degrees:

tan(72.7919) ≈ 3.0314 (rounded to four decimal places)

Finally, multiply the result by 15:

15 * 3.0314 ≈ 45.471 (rounded to three decimal places)

So, the simplified value of the expression is approximately 45.471.