Question

Sina, + tga _________ =1+cos2 Tga

Answer 1

$\frac{sin\alpha+tg\alpha}{tg\alpha}=\frac{sin\alpha}{tg\alpha}+\frac{tg\alpha}{tg\alpha}=\\ \frac{sin\alpha}{\frac{sin\alpha}{cos\alpha}}+1=1+sin\alpha\cdot\frac{cos\alpha}{sic\alpha}}=1+cos\alpha$

Answer 2

Let's solve the equation you provided:

Sina + tga(θ) = 1 + cos^2(θ)

First, let's simplify the equation using trigonometric identities. The identity we'll use here is:

1 + cos^2(θ) = sin^2(θ)

Now, substitute sin^2(θ) for 1 + cos^2(θ) in the equation:

Sina + tga(θ) = sin^2(θ)

Next, let's use another trigonometric identity:

sin^2(θ) = 1 - cos^2(θ)

So, we can rewrite the equation as:

Sina + tga(θ) = 1 - cos^2(θ)

Now, let's isolate tga(θ) by moving Sina to the other side of the equation:

tga(θ) = 1 - cos^2(θ) - Sina

And that's the simplified form of the equation.