Question

7x-4 x-4 ------ -- ---- == 0 x+5 x+5 Как решить? 3 1 ----- + ---- == 0 x-3 x+3

Answer 1

Решение смотри на фото. Как я понял там минус между дробями

Answer 2

To solve the first equation, we need to find the values of "x" that make the equation true. The given equation is:

(7x - 4) / (x + 5) - (4x - 4) / (x + 5) = 0

Step 1: Find a common denominator for the fractions, which is (x + 5).

Step 2: Combine the fractions over the common denominator:

[(7x - 4) - (4x - 4)] / (x + 5) = 0

Step 3: Simplify the expression inside the parentheses:

(7x - 4 - 4x + 4) / (x + 5) = 0

Step 4: Combine like terms:

(3x) / (x + 5) = 0

Now, for the equation to be true, the numerator must be equal to 0. So:

3x = 0

Step 5: Solve for "x":

x = 0

Thus, the solution to the first equation is x = 0.

Now, let's move on to the second equation:

(3 / (x - 3)) + (1 / (x + 3)) = 0

Step 1: Find a common denominator for the fractions, which is (x - 3)(x + 3).

Step 2: Combine the fractions over the common denominator:

[(3 * (x + 3)) + (1 * (x - 3))] / (x - 3)(x + 3) = 0

Step 3: Simplify the expression inside the parentheses:

(3x + 9 + x - 3) / (x - 3)(x + 3) = 0

Step 4: Combine like terms:

(4x + 6) / (x - 3)(x + 3) = 0

Now, for the equation to be true, the numerator must be equal to 0. So:

4x + 6 = 0

Step 5: Solve for "x":

4x = -6

x = -6 / 4

x = -3 / 2

Thus, the solution to the second equation is x = -3/2.

So, the solutions to the given equations are x = 0 and x = -3/2.