Question

Sin П/6+ корень 2 cos п/4-корень 3 ctgП/3

Answer 1

$Sin\frac{\pi }{6}+\sqrt{2}Cos\frac{\pi }{4}-\sqrt{3}Ctg\frac{\pi }{3}=\frac{1}{2}+\sqrt{2}*\frac{\sqrt{2} }{2}-\sqrt{3}*\frac{1}{\sqrt{3} } =\frac{1}{2}+1-1=0,5$

Answer 2

To solve the expression, let's use the following trigonometric identities:

1. sin(π/6) = 1/2
2. cos(π/4) = √2 / 2
3. √3
4. ctg(π/3) = 1 / tan(π/3) = 1 / √3

Now, let's plug in these values:

sin(π/6) + √2 cos(π/4) - √3 ctg(π/3)

= 1/2 + √2 * (√2 / 2) - √3 * (1 / √3)

= 1/2 + 1 - 1

= 1/2

So, the simplified value of the expression is 1/2.