Question

(4х-11) (4х+11) -16в квадрате -7х+41 при х=120

Answer 1

$16 {x}^{2} - 121 - {16}^{2} - 7x + 41 = - 7x - 80 = - 7 \times 120 - 80 = - 840 - 80 = - 920$

Answer 2

To evaluate the expression for the given values of x, you simply substitute the value of x into the expression and perform the calculations. Let's calculate the result step by step:

Given expression: (4x-11) * (4x+11) - 16v^2 - 7x + 41

Given value: x = 120

Step 1: Substitute the value of x into the expression (4 * 120 - 11) * (4 * 120 + 11) - 16v^2 - 7 * 120 + 41

Step 2: Perform the calculations inside the parentheses (480 - 11) * (480 + 11) - 16v^2 - 840 + 41

Step 3: Continue evaluating 469 * 491 - 16v^2 - 799

Step 4: Calculate the product 230179 - 16v^2 - 799

Step 5: Subtract 799 from the product 229380 - 16v^2

Now the expression is in the form "229380 - 16v^2." If you have a value for 'v', you can further substitute it in to get the final result. If you have a specific value for 'v', please provide it, and I can help you calculate the final result.