Question

1\3<3^3+x<9 с решением

Answer 1

-1<3+х<2
-4<х<-1
//./....//

Answer 2

To solve the inequality $\frac{1}{3} < 3^3 + x < 9$, we need to find the range of values for $x$ that satisfy the inequality.

Step 1: Evaluate the expression inside the inequality. $3^3 = 27$

Step 2: Rewrite the inequality with the evaluated expression: $\frac{1}{3} < 27 + x < 9$

Step 3: Simplify the inequality. Subtract 27 from all parts of the inequality: $\frac{1}{3} - 27 < x < 9 - 27$

Step 4: Perform the arithmetic operations: $\frac{1}{3} - 27 = \frac{1}{3} - \frac{81}{3} = -\frac{80}{3}$ $9 - 27 = -18$

The simplified inequality is now: $-\frac{80}{3} < x < -18$

So, the solution for the inequality is $-\frac{80}{3} < x < -18$.