Question

А-(4а-11)+(9-2а)=20-5а

Answer 1

A-(4a-11)+(9-2a)=20-5a
a-4a+11+9-2a=20-5a
-5a+11+9=20-5a
-5a+20=20-5a
-5a+5a=20-20
0=0

Answer 2

a-4a+11+9-2a-20+5a=0

0=0

Answer 3

Let's solve the given equation step-by-step:

А - (4а - 11) + (9 - 2а) = 20 - 5а

First, let's simplify the equation by removing the parentheses:

А - 4а + 11 + 9 - 2а = 20 - 5а

Next, combine like terms:

(А - 4а) + (-2а) + (11 + 9) = 20 - 5а

Now, combine the coefficients of 'а':

-5а + 20 = 20 - 5а

At this point, the variable 'а' is eliminated from both sides of the equation. However, the equation is also an identity. This means that the equation holds true for any value of 'а'. It's an identity because the left-hand side (LHS) simplifies to -5а + 20, and the right-hand side (RHS) simplifies to 20 - 5а, and they are equal.

So, the solution to this equation is that it holds true for all values of 'а', but there is no specific value of 'а' that satisfies the equation.