Question

{3х+(k-1)=k+1, {(k+1)x+y=3 Смотреть ответ hcfnfc hcfnfc ............................

Answer 1

It looks like your equations are not completely clear due to some formatting issues, but I will do my best to help you understand and possibly solve them.

From what I can decipher, you have two equations:

1. $3x + (k - 1) = k + 1$
2. $(k + 1)x + y = 3$

It seems like you want to solve these two equations for the variables $x$, $y$, and $k$.

Let's start with solving these equations step-by-step:

Step 1: Solve the first equation for $k$: $3x + (k - 1) = k + 1$

To isolate $k$, first, move all terms involving $k$ to one side:

$3x + k - 1 - k = k + 1 - k$

Simplify:

$3x - 1 = 1$

Now, isolate $k$ on one side:

$k = 3x - 1$

Step 2: Substitute the value of $k$ from the first equation into the second equation:

$(k + 1)x + y = 3$

Substitute $k = 3x - 1$ into the equation:

$(3x - 1 + 1)x + y = 3$

Simplify:

$3x^2 + y = 3$

Step 3: Solve for $y$ in terms of $x$:

$y = 3 - 3x^2$

So, after solving the equations, we have found expressions for $k$ and $y$ in terms of $x$:

$k = 3x - 1$

$y = 3 - 3x^2$

Now, if you need a specific solution for $x$, $y$, and $k$, you'll need additional information or constraints to solve for numerical values. If there was more context or if there were additional equations, please provide them, and I'll be glad to help further.