Question

1. c(2a-2c)+a(3c-a)-2(a-c во второй степени) при a= -0.1 c=0.7

Answer 1

Ответ : -1,36;

Решение - на фото

Answer 2

To evaluate the expression c(2a-2c) + a(3c-a) - 2(a-c)^2 with specific values for a and c, which are a = -0.1 and c = 0.7, follow these steps:

1. Replace all instances of 'a' with '-0.1'
2. Replace all instances of 'c' with '0.7'
3. Perform the arithmetic operations.

Let's calculate it step by step:

Step 1: Replace 'a' with '-0.1' c(2(-0.1) - 2c) + (-0.1)(3c - (-0.1)) - 2((-0.1) - c)^2

Step 2: Replace 'c' with '0.7' 0.7(2(-0.1) - 2(0.7)) + (-0.1)(3(0.7) - (-0.1)) - 2((-0.1) - 0.7)^2

Step 3: Perform the arithmetic operations 0.7(-0.2 - 1.4) + (-0.1)(2.1 - (-0.1)) - 2(-0.8)^2 0.7(-1.6) + (-0.1)(2.1 + 0.1) - 2(0.64) -1.12 - 0.22 - 1.28 -2.62

So, when a = -0.1 and c = 0.7, the value of the expression c(2a-2c) + a(3c-a) - 2(a-c)^2 is -2.62.