Question

1)0.8корень400+1\7корень49 2)корень0.36*корень16 3)корень3 в 6 степени*2 в 4 ст 4)корень 27*корень3-корень 28\корень 7

Answer 1

1 решение 0.8*20+1/7*7=16+1=17

2 решение корень из 9/25*4=3/5*4=12/5=2.4

3 решение корень из 3 в 6 степени есть 3^3. 3^3*2^4=2*6^3=2*216=432

4 решение корень из 81 -корень из 4=9-2=7

Answer 2

Let's simplify each of the given expressions step by step:

1. $0.8\sqrt{400} + \frac{1}{7}\sqrt{49}$

First, simplify the square roots:

$0.8 \cdot 20 + \frac{1}{7} \cdot 7$

Now, perform the multiplications:

$16 + 1$

Finally, add the numbers:

$17$

So, the result is $17$.

2. $\sqrt{0.36} \cdot \sqrt{16}$

First, simplify the square roots:

$0.6 \cdot 4$

Now, perform the multiplication:

$2.4$

So, the result is $2.4$.

3. $\sqrt[6]{3} \cdot 2^4$

First, simplify the exponentiation:

$\sqrt[6]{3} \cdot 16$

Now, calculate the sixth root of 3 (approximately 1.157) and perform the multiplication:

$1.157 \cdot 16$

Finally, calculate the result:

$18.512$

So, the result is approximately $18.512$.

4. $\sqrt{27} \cdot \sqrt{3} - \frac{\sqrt{28}}{\sqrt{7}}$

First, simplify the square roots:

$3\sqrt{3} - \frac{\sqrt{4 \cdot 7}}{\sqrt{7}}$

Now, perform the multiplication and simplify further:

$3\sqrt{3} - \frac{2}{\sqrt{7}}$

To rationalize the denominator, multiply both the numerator and the denominator by $\sqrt{7}$:

$3\sqrt{3} - \frac{2\sqrt{7}}{7}$

So, the result is $3\sqrt{3} - \frac{2\sqrt{7}}{7}$. This is the final simplified expression.