Question

16/25-x2=0 25x2-(5x+1)2=0

Answer 1

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Answer 2

Решение

1) 16/25-х²=0

16=0

2) 25x²-(5x+1)²=0

25х²-(25х²+10х+1)=0

25х²-25х²-10х-1=0

-10х-1=0

-10х=1

Ответ

1)х∈∅

2) х=-1/10 ≈ -0,1

Answer 3

To solve the equations, let's follow these steps:

1. Solve the first equation: 16/25 - x^2 = 0
2. Solve the second equation: 25x^2 - (5x + 1)^2 = 0

Equation 1: 16/25 - x^2 = 0

To solve this equation, we need to isolate x^2:

16/25 - x^2 = 0

Subtract 16/25 from both sides:

-x^2 = -16/25

Now, multiply both sides by -1 to solve for x^2:

x^2 = 16/25

Take the square root of both sides:

x = ±√(16/25)

x = ±(√16)/(√25)

x = ±(4/5)

So the solutions for Equation 1 are:

x = 4/5 (positive solution) x = -4/5 (negative solution)

Equation 2: 25x^2 - (5x + 1)^2 = 0

This equation is a quadratic equation, so we'll need to expand and simplify it before solving:

25x^2 - (5x + 1)^2 = 0

Expand the square: (a - b)^2 = a^2 - 2ab + b^2

25x^2 - (25x^2 + 2 * 5x * 1 + 1^2) = 0

25x^2 - (25x^2 + 10x + 1) = 0

Now, distribute the negative sign:

25x^2 - 25x^2 - 10x - 1 = 0

Simplify the equation:

-10x - 1 = 0

Now, add 1 to both sides to isolate -10x:

-10x = 1

Finally, divide by -10 to solve for x:

x = -1/10

So the solution for Equation 2 is:

x = -1/10

To summarize:

Equation 1 solutions: x = 4/5 x = -4/5

Equation 2 solution: x = -1/10