Question

Sin(П/2+a)*ctg(П/2-a) /cos(-a) ​

Answer 1

sin(п/2 + a)*ctg(п/2 - a)/cos(-a)=cosa*tga/cosa=tga

Answer 2

To simplify the given expression, let's use some trigonometric identities.

1. sin(π/2 + a) = cos(a)
2. ctg(π/2 - a) = tan(a)
3. cos(-a) = cos(a) (cosine function is even)

Now, we can substitute these identities into the expression:

(cos(a) * tan(a)) / cos(a)

The cos(a) terms cancel out, leaving us with:

tan(a)

So, the simplified form of the expression is just "tan(a)."