Question

Решите уравнение 2х^-200=0

Answer 1

$2x^2-100=0\ /:2\\\\x^2-100=0\\\\(x-10)(x+10)=0\\\\x-10=0 \ \ \ \ \ \ \ x+10=0\\\\x=10 \ \ \ \ \ \ \ \ \ \ \ \ x=-10$

Ответ : - 10; 10

Answer 2

To solve the equation 2x^(-200) = 0, we need to find the value of x that satisfies this equation. However, notice that the term x^(-200) represents the reciprocal of x raised to the power of 200, and this expression can never be equal to zero for any nonzero value of x.

The reason is that x^(-200) is equivalent to 1/x^200, and dividing any nonzero number (e.g., 1) by a nonzero number (x^200) will always yield a nonzero result. Therefore, there is no real value of x that satisfies the equation 2x^(-200) = 0.

In conclusion, the equation 2x^(-200) = 0 has no real solutions.