Question

(x+4) (x во второй степени - 4х +16)

Answer 1

$x {}^{3} + 4 { }^{3} \\ x {}^{3} + 64$

Answer 2

х³-4х²+16х+4х²-16х+64

-4х² и 4х² - противоположные, поэтому мы их просто зачеркиваем.

х³+16х-16х+64

так же убираем 16х и -16х

Ответ: х³+64

Answer 3

To expand the expression, you'll need to use the distributive property of multiplication. Multiply each term in the first parentheses by each term in the second parentheses. Let's go step-by-step:

Expression: (x + 4) (x^2 - 4x + 16)

1. First, distribute x from the first parentheses to each term in the second parentheses: x * x^2 = x^3 x * (-4x) = -4x^2 x * 16 = 16x

So, we have: x^3 - 4x^2 + 16x

2. Next, distribute 4 from the first parentheses to each term in the second parentheses: 4 * x^2 = 4x^2 4 * (-4x) = -16x 4 * 16 = 64

So, we have: 4x^2 - 16x + 64

Now, combine the two results:

Final expression: x^3 - 4x^2 + 16x + 4x^2 - 16x + 64

Notice that the terms "-4x^2" and "+4x^2" cancel each other out, as well as "-16x" and "+16x," leaving us with:

Final simplified expression: x^3 + 64