Question

Решите уравнение : (y-3)(5y^2-2)=0

Answer 1

Два случая

1) у-3=0

у1=3

2) 5у^2-2=0

5у^2=2

у^2=2/5

у2=√10/5

у-3=-√10/5

Answer 2

Решение

(y-3)(5y²-2)=0

у-3=0

у=3 ,

5у²-2=0

у=√10/5

у=-√10/5

Ответ

у1=-√10/5 , у2=√10/5 , у3=3

Answer 3

To solve the equation $(y-3)(5y^2-2) = 0$, we need to find the values of $y$ that make the entire expression equal to zero. To do this, we set each factor to zero and solve for $y$.

Step 1: Set each factor to zero:

1. $y - 3 = 0$
2. $5y^2 - 2 = 0$

Step 2: Solve for $y$ in each equation:

1. $y - 3 = 0$ Add 3 to both sides to isolate $y$: $y = 3$

2. $5y^2 - 2 = 0$ Add 2 to both sides to isolate $5y^2$: $5y^2 = 2$

Divide both sides by 5 to solve for $y^2$: $y^2 = \frac{2}{5}$

Now, to find the values of $y$, take the square root of both sides:

$y = \pm \sqrt{\frac{2}{5}}$

So, the solutions to the equation are $y = 3$, $y = \sqrt{\frac{2}{5}}$, and $y = -\sqrt{\frac{2}{5}}$.