Question

1)(a-3)^2= 2)(2x+y)^2= 3)(5b-4x)(5b+4x)= 1)4a(a-2)-(a-4)^2=

Answer 1

1)(a-3)²=a²-6a+9

2)(2x+y)²=4x²+4xy+y²

3)(5b-4x)(5b+4x)=25b²-16x²

1)4a(a-2)-(a-4)²=4a²-8a-a²+8a-16=3a²+8a

Answer 2

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Answer 3

Let's solve each of the equations one by one:

1. (a-3)^2 = To solve this, we need to expand the expression: (a-3)^2 = (a-3)(a-3) = a^2 - 6a + 9

2. (2x+y)^2 = Expanding the expression: (2x+y)^2 = (2x+y)(2x+y) = 4x^2 + 2xy + y^2

3. (5b-4x)(5b+4x) = This is a difference of squares, which can be solved using the formula: (a^2 - b^2) = (a + b)(a - b) In this case, a = 5b and b = 4x: (5b-4x)(5b+4x) = (5b)^2 - (4x)^2 = 25b^2 - 16x^2

4. 4a(a-2) - (a-4)^2 = Expand the expression: 4a(a-2) - (a-4)^2 = 4a^2 - 8a - (a^2 - 8a + 16) = 4a^2 - 8a - a^2 + 8a - 16 = 3a^2 - 16

So, the expanded forms of the given expressions are:

1. (a-3)^2 = a^2 - 6a + 9
2. (2x+y)^2 = 4x^2 + 2xy + y^2
3. (5b-4x)(5b+4x) = 25b^2 - 16x^2
4. 4a(a-2) - (a-4)^2 = 3a^2 - 16