Question

Решить неравенство:1+x<2≤3-x​

Answer 1

1+x< 2 ≤3-x​

1+x < 2  ⇒ х< 1

3-x ​≥ 2 ⇒ x ≤ 1

х∈(-∞; 1)

Answer 2

To solve the compound inequality 1 + x < 2 ≤ 3 - x, we'll break it down into two separate inequalities and solve each one step-by-step.

First inequality: 1 + x < 2 Subtract 1 from both sides to isolate x: x < 2 - 1 x < 1

Second inequality: 2 ≤ 3 - x Subtract 2 from both sides to isolate -x:

• x ≤ 2 - 2
• x ≤ 0

Now, we have two separate inequalities:

1. x < 1
2. -x ≤ 0

To find the solution for x, we need to find the intersection of these two inequalities. Since -x ≤ 0 is true for all non-positive values of x, we can simplify the solution to:

x ≤ 0

Therefore, the solution for the compound inequality 1 + x < 2 ≤ 3 - x is x ≤ 0.