Question

4a^2-4ab+b^2:4a^2-b^2 при а =1:11 b=-9:11​

Answer 1

4а²-4ав+в²/4а²-в²=(2а-в)²/(2а-в)(2а+в)=2а-в/2а+в

подставляем значения

2/11-9/11  / 2/11+9/11=-7/11

Answer 2

$\frac{ {(2x - y)}^{2} }{(2x - y)(2x + y)} = \frac{2x - y}{2x + y}$
$\frac{ \frac{2}{11} + \frac{9}{11} }{ \frac{2}{11} - \frac{9}{11} } = - \frac{11}{7}$

Answer 3

To evaluate the expression (4a^2 - 4ab + b^2) / (4a^2 - b^2) when a = 1 and b = -9, we first need to substitute these values into the expression:

Expression: (4a^2 - 4ab + b^2) / (4a^2 - b^2)

Substitute a = 1 and b = -9:

(4 * 1^2 - 4 * 1 * (-9) + (-9)^2) / (4 * 1^2 - (-9)^2)

Now, calculate each part step-by-step:

(4 * 1^2) = 4 (4 * 1 * (-9)) = -36 ((-9)^2) = 81 (4 * 1^2 - 4 * 1 * (-9) + (-9)^2) = 4 - (-36) + 81 = 4 + 36 + 81 = 121

(4 * 1^2) = 4 ((-9)^2) = 81 (4 * 1^2 - (-9)^2) = 4 - 81 = -77

Now, divide the two results:

(4a^2 - 4ab + b^2) / (4a^2 - b^2) = 121 / -77 ≈ -1.5714

So, when a = 1 and b = -9, the expression (4a^2 - 4ab + b^2) / (4a^2 - b^2) evaluates to approximately -1.5714.