Question

Алгебра 8 класс 1) y=x2+6x+8 2) y=-2x^-8x-8

Answer 1

Ответ:

Нет чётко поставленного задания.

Объяснение:

Answer 2

To clarify, it seems like you have two quadratic equations in mind. However, the second equation you provided seems to be incomplete or written with a typo. It should be written as:

2. y = -2x^2 - 8x - 8

Let's proceed with solving both equations:

1. y = x^2 + 6x + 8

To solve this quadratic equation, you can use factoring, completing the square, or the quadratic formula. Let's use the quadratic formula:

The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, the coefficients are: a = 1 (coefficient of x^2 term) b = 6 (coefficient of x term) c = 8 (constant term)

Now, plug the values into the quadratic formula:

x = (-(6) ± √(6^2 - 4 * 1 * 8)) / 2 * 1 x = (-6 ± √(36 - 32)) / 2 x = (-6 ± √4) / 2 x = (-6 ± 2) / 2

Now, find the two possible values of x:

1. x = (-6 + 2) / 2 = -4 / 2 = -2
2. x = (-6 - 2) / 2 = -8 / 2 = -4

So, the solutions for the equation y = x^2 + 6x + 8 are x = -2 and x = -4.

2. y = -2x^2 - 8x - 8

Now, let's solve the second quadratic equation. We can use the same quadratic formula:

a = -2 (coefficient of x^2 term) b = -8 (coefficient of x term) c = -8 (constant term)

x = (-( -8 ) ± √((-8)^2 - 4 * -2 * -8)) / 2 * -2 x = (8 ± √(64 - 64)) / -4 x = (8 ± √0) / -4 x = (8 ± 0) / -4

Since the discriminant (the term inside the square root) is zero, there is only one real root:

1. x = (8 + 0) / -4 = 8 / -4 = -2

So, the solution for the equation y = -2x^2 - 8x - 8 is x = -2.