Question

3xв квадрате -bx+27=0

Answer 1

Ответ:в ответе два корня

Объяснение:

Answer 2

To solve the quadratic equation 3x^2 - bx + 27 = 0, we need to find the value(s) of 'x' that satisfy the equation. The general form of a quadratic equation is ax^2 + bx + c = 0, where 'a', 'b', and 'c' are constants.

In this case, 'a' is 3, 'b' is -b, and 'c' is 27. To find the values of 'x', we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Now, let's apply the formula to find 'x':

x = (b ± √(b^2 - 4ac)) / 2a

x = (-(-b) ± √((-b)^2 - 4 * 3 * 27)) / (2 * 3)

x = (b ± √(b^2 - 324)) / 6

The solutions for 'x' depend on the value of 'b'. Since you didn't provide a specific value for 'b', I'll keep the solution in terms of 'b':

x = (b ± √(b^2 - 324)) / 6

Please provide the value of 'b' if you want to get the specific solutions for 'x'.