Question

15(x+2)=6(2x+7) 6(x-3)-10=2(x+2)

Answer 1

15x+30=12x+42

15x-12x=42-30

3x=12

x=4

6x-28=2x+4

6x-2x=4+28

4x=32

x=8

Answer 2

Ответ:

15(x+2) = 6(2x + 7)

15x-12x=42-30

3x=12|:3

x=4

6(x-3)-10=2(x+2)

6x-2x=4+10+18

4x=32|:4

x=8

Answer 3

To solve the equations, let's start with the first one:

1. 15(x + 2) = 6(2x + 7)

Step 1: Distribute the numbers on the right side. 15x + 30 = 12x + 42

Step 2: Move all the x terms to one side and the constant terms to the other side. 15x - 12x = 42 - 30 3x = 12

Step 3: Divide both sides by 3 to solve for x. x = 12 / 3 x = 4

Now, let's move on to the second equation:

2. 6(x - 3) - 10 = 2(x + 2)

Step 1: Distribute the numbers on the left and right side. 6x - 18 - 10 = 2x + 4

Step 2: Combine like terms. 6x - 28 = 2x + 4

Step 3: Move all the x terms to one side and the constant terms to the other side. 6x - 2x = 4 + 28 4x = 32

Step 4: Divide both sides by 4 to solve for x. x = 32 / 4 x = 8

So, the solutions to the equations are: x = 4 (for the first equation) x = 8 (for the second equation)