Question

Cos 330°-sin 225°памогите решит пж​

Answer 1

Ответ:

Объяснение:

сos330°-sin225°=cos(360°-30°)-sin(180°+45°)=cos30°+sin45°=

=(√3/2)+(√2/2)=(√3+√2)/2.

Answer 2

To solve this expression, let's evaluate each trigonometric term separately:

1. cos(330°): We know that cos(360° - θ) = cos(θ). So, cos(330°) is equal to cos(360° - 30°). Since cos(30°) = (√3)/2, we have: cos(330°) = cos(360° - 30°) = cos(30°) = (√3)/2.

2. sin(225°): We know that sin(180° + θ) = -sin(θ). So, sin(225°) is equal to -sin(45°). Since sin(45°) = (√2)/2, we have: sin(225°) = -sin(45°) = -((√2)/2) = -√2/2.

Now, let's substitute these values back into the original expression:

cos(330°) - sin(225°) = (√3)/2 - (-√2/2)

To simplify the expression further, we can rewrite the subtraction as addition:

cos(330°) - sin(225°) = (√3)/2 + √2/2

To add these terms, we need a common denominator:

cos(330°) - sin(225°) = (√3 + √2)/(2)

Therefore, the simplified value of cos(330°) - sin(225°) is (√3 + √2)/2.