Question

(х-3)²+12х=(х-2)(х+2) уравнегие ​

Answer 1

Объяснение:

(х-3)²+12х=(х-2)(х+2)

x²-6x+9+12x=x²-4

6x=(-13)

x=(-13/6)

x=(-2 1/6)

x=2,1(6)

Answer 2

Ответ:x=-1,2,6

Объяснение:(x-2)^2(x-3)-12(x-2)=0

(x-2)((x-2)(x-3)-12)=0

(x-2)(x^2-5x-6)=0

(x-2)(x+1)(x-6)=0

Ответ: x=-1,2,6

Answer 3

To solve the equation (х-3)² + 12х = (х-2)(х+2), we'll first expand the left side and simplify the right side, and then try to find the value(s) of х that satisfy the equation.

Step 1: Expand the left side of the equation (х-3)² + 12х = (х-3)(х-3) + 12х = х² - 6х + 9 + 12х = х² + 6х + 9

Step 2: Simplify the right side of the equation (х-2)(х+2) = х² + 2х - 2х - 4 = х² - 4

Now the equation becomes: х² + 6х + 9 = х² - 4

Step 3: Move all the terms to one side to set the equation to zero х² - х² + 6х - 6х + 9 + 4 = 0

Step 4: Simplify the equation 9 + 4 = 0

Step 5: The equation is inconsistent (no х term). There is no solution that satisfies the equation.

Therefore, the equation (х-3)² + 12х = (х-2)(х+2) has no solution.