Question

-117 5/11t+100,1k+176 4/9t при t=-79,8, k=50

Answer 1

$\displaystyle \tt -117\frac{5}{11}t+100,1k+176\frac{4}{9}t=t\cdot\bigg(175\frac{143}{99}-117\frac{45}{99}\bigg)+100,1k=\\\\=58\frac{98}{99}t+100,1k;\\\\\\npu \ \ \ t=-79,8 \ \ u \ \ k=50:\\\\\\58\frac{98}{99}\cdot(-79,8)+100,1\cdot50=-\frac{5840}{99}\cdot\frac{798}{10}+5005=-\frac{584\cdot266}{33}+5005=\\\\=5005-4707\frac{13}{33}=297\frac{20}{33};$

Answer 2

To calculate the values of the expressions when t = -79.8 and k = 50, we can substitute these values into the given expressions. Let's start with the first expression:

Expression 1: -117 + 5/11t + 100

Substitute t = -79.8 into the expression: -117 + 5/11(-79.8) + 100

Now, perform the calculations: -117 + (-363/11) + 100 -117 - 33 + 100 -117 + 67 = -50

So, when t = -79.8, the value of the first expression is -50.

Next, let's calculate the second expression:

Expression 2: 1k + 176 4/9t

Substitute t = -79.8 and k = 50 into the expression: 1(50) + 176 + 4/9(-79.8)

Now, perform the calculations: 50 + 176 - 35.2 = 190.8

So, when t = -79.8 and k = 50, the value of the second expression is approximately 190.8.