Question

X2+4/5x+3/25=0 Хелп плиз)

Answer 1

Ответ:

Ответ и решение в закрепе

Answer 2

To solve the quadratic equation x^2 + (4/5)x + (3/25) = 0, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 4/5, and c = 3/25.

Plugging in these values into the quadratic formula, we get:

x = (-(4/5) ± √((4/5)^2 - 4(1)(3/25))) / (2(1))

Simplifying further:

x = (-4/5 ± √(16/25 - 12/25)) / 2

x = (-4/5 ± √(4/25)) / 2

x = (-4/5 ± (2/5)) / 2

Now, we have two possible solutions:

x1 = (-4/5 + 2/5) / 2 = -2/5 / 2 = -1/5

x2 = (-4/5 - 2/5) / 2 = -6/5 / 2 = -3/5

Therefore, the solutions to the quadratic equation x^2 + (4/5)x + (3/25) = 0 are x = -1/5 and x = -3/5.