Question

(х+1)(х-1)(х-2)-(х3+7х)(х-4)-2-2х

Answer 1

(x²-1)(x-2)-(x³+7x)(x-4)-2-2x= x³-2x²-x+2-x⁴+4x³-7x²+28x-2-2x= -x⁴+5x³-9x²+25x

Answer 2

Ответ:

x²-42x²-3x

Объяснение:

(x²-1)(x-2)-(3x+7x)(4x)-2-2x

x³-2x²-x+2-10x•4x-2-2x

x³-2x²-x+2-40x²-2-2x

x³-42x²-3x

Answer 3

Let's simplify the expression step by step:

1. Expand the first set of parentheses: (x + 1)(x - 1)(x - 2) = (x^2 - x + x - 1)(x - 2) = (x^2 - 1)(x - 2) = x^3 - 2x^2 - x + 2

2. Expand the second set of parentheses: (x^3 + 7x)(x - 4) = x^4 - 4x^3 + 7x^2 - 28x

Now the expression becomes:

(x^3 - 2x^2 - x + 2) - (x^4 - 4x^3 + 7x^2 - 28x) - 2 - 2x

3. Combine like terms:

x^3 - 2x^2 - x + 2 - x^4 + 4x^3 - 7x^2 + 28x - 2 - 2x

4. Group the terms with the same exponent:

(-x^4 + x^3) + (4x^3 - 2x^2) + (-7x^2 - x) + (28x - 2 - 2x) + 2

5. Simplify each group:

-x^4 + x^3 + 4x^3 - 2x^2 - 7x^2 - x + 28x - 2 - 2x + 2

6. Combine like terms once again:

-x^4 + 5x^3 - 9x^2 + 25x

The simplified expression is:

-x^4 + 5x^3 - 9x^2 + 25x