Question

-2х=6 4х--3 (х-2)(х+3)=0

Answer 1

Ответ:

-2х=6

х=6:(-2)

х=-3

(х-2)(х+3)=0

х^2+3х-2х-6=0

х^2+х-6=0

Д= 1^2-4*-6*1=1+24=25

х1=(-1+5):2=4:2=2

х2=(-1-5):2=-6:2=-3

Answer 2

Let's solve each equation step by step:

1. -2x = 6

To solve for x, we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by -2:

-2x/-2 = 6/-2

This simplifies to:

x = -3

So the solution to the equation -2x = 6 is x = -3.

2. 4x - (-3)

To simplify this expression, we can remove the double negative:

4x + 3

There's no equation to solve here; it's just an expression.

3. (x-2)(x+3) = 0

To solve this quadratic equation, we set each factor equal to zero and solve for x:

x - 2 = 0 or x + 3 = 0

Solving the first equation:

x - 2 = 0

Adding 2 to both sides:

x = 2

Solving the second equation:

x + 3 = 0

Subtracting 3 from both sides:

x = -3

So the solutions to the equation (x-2)(x+3) = 0 are x = 2 and x = -3.

Therefore, the solutions to the equations are x = -3, x = 2, and the expression 4x - (-3) simplifies to 4x + 3.