Question

F(x)=2x³+5x²-2x=1 f(x) f(0) f(-1)

Answer 1

Если задание найти значение функции от заданного значения аргумента :

f(x)=2x³+5x²-2x+1,

f(0)=2*0+5*0-2*0+1,

f(0)=1.

f(-1)=2(-1)³+5(-1)²-2(-1)+1=-2+5+2+1, f(-1)=6

Answer 2

To evaluate the function $f(x) = 2x^3 + 5x^2 - 2x - 1$ at various points, we can substitute the values into the function and calculate the corresponding output.

1. $f(x)$: $f(x) = 2x^3 + 5x^2 - 2x - 1$

2. $f(0)$: To find $f(0)$, substitute $x = 0$ into the function: $f(0) = 2(0)^3 + 5(0)^2 - 2(0) - 1$ Simplifying, we get: $f(0) = 0 + 0 - 0 - 1 = -1$

   Therefore, $f(0) = -1$.

3. $f(-1)$: To find $f(-1)$, substitute $x = -1$ into the function: $f(-1) = 2(-1)^3 + 5(-1)^2 - 2(-1) - 1$ Simplifying, we get: $f(-1) = 2(-1) + 5(1) + 2 - 1$ $f(-1) = -2 + 5 + 2 - 1 = 4$

   Therefore, $f(-1) = 4$.

In summary: $f(x) = 2x^3 + 5x^2 - 2x - 1$ $f(0) = -1$ $f(-1) = 4$