Question

(2а-3)степень6(2а-3)6​

Answer 1

Объяснение:

если что то не понятно пиши

Answer 2

To simplify the expression (2a-3)^6, we can use the binomial theorem, which states that:

(a + b)^n = Σ[n choose k] * a^(n-k) * b^k

Where: n is the exponent k is the index of summation (ranging from 0 to n) [n choose k] is the binomial coefficient, which can be calculated as n! / (k! * (n - k)!), where "!" denotes factorial.

In our case, a = 2a, b = -3, and n = 6. Plugging these values into the binomial theorem formula, we get:

(2a - 3)^6 = Σ[6 choose k] * (2a)^(6-k) * (-3)^k

Now, let's calculate each term for k = 0 to k = 6 and then add them together:

For k = 0: 6 choose 0 = 1 (2a)^(6-0) = (2a)^6 = 64a^6 (-3)^0 = 1

Term for k = 0: 1 * 64a^6 * 1 = 64a^6

For k = 1: 6 choose 1 = 6 (2a)^(6-1) = (2a)^5 = 32a^5 (-3)^1 = -3

Term for k = 1: 6 * 32a^5 * (-3) = -576a^5

For k = 2: 6 choose 2 = 15 (2a)^(6-2) = (2a)^4 = 16a^4 (-3)^2 = 9

Term for k = 2: 15 * 16a^4 * 9 = 2160a^4

For k = 3: 6 choose 3 = 20 (2a)^(6-3) = (2a)^3 = 8a^3 (-3)^3 = -27

Term for k = 3: 20 * 8a^3 * (-27) = -4320a^3

For k = 4: 6 choose 4 = 15 (2a)^(6-4) = (2a)^2 = 4a^2 (-3)^4 = 81

Term for k = 4: 15 * 4a^2 * 81 = 4860a^2

For k = 5: 6 choose 5 = 6 (2a)^(6-5) = (2a)^1 = 2a (-3)^5 = -243

Term for k = 5: 6 * 2a * (-243) = -1458a

For k = 6: 6 choose 6 = 1 (2a)^(6-6) = (2a)^0 = 1 (-3)^6 = 729

Term for k = 6: 1 * 1 * 729 = 729

Now, add all the terms together:

64a^6 - 576a^5 + 2160a^4 - 4320a^3 + 4860a^2 - 1458a + 729

So, the simplified expression for (2a - 3)^6 is:

64a^6 - 576a^5 + 2160a^4 - 4320a^3 + 4860a^2 - 1458a + 729