Question

(2x-1)*(x²-16)=0 X=?

Answer 1

Ответ:

(2х-1)(х^2 - 16)=0

2х-1=0

2х=1

х=1/2

х^2-16=0

х^2 =16

х1=-4

х2=4

Answer 2

Ответ:

(2x-1) =0 или (x2-16) =0

Если 2x-1, то ответ 1:2, если икс в квадрате мину 16, то икс равен 4 или минус 4

Answer 3

To find the value of x that satisfies the equation (2x - 1) * (x² - 16) = 0, we can set each factor equal to zero and solve for x.

Setting the first factor, 2x - 1, equal to zero: 2x - 1 = 0 2x = 1 x = 1/2

Setting the second factor, x² - 16, equal to zero: x² - 16 = 0 x² = 16 x = ±√16 x = ±4

So, the solutions to the equation are x = 1/2, x = 4, and x = -4.