Question

(2а+2в /в) ×( 1/а-в-1/а+в)​

Answer 1

Во вторых скобках всё сокращается, а дальше там уже будет просто)

Объяснение:

Answer 2

To simplify the expression (2а+2в / в) × (1 / а-в-1 / а+в), we can start by simplifying each fraction individually and then perform the multiplication.

Let's simplify each fraction first:

2а + 2в / в can be written as (2ав + 2в²) / в.

1 / а - в - 1 / а + в can be written as (1 - в² + 1) / (а - в) or (2 - в²) / (а - в).

Now, let's multiply these two fractions:

[(2ав + 2в²) / в] × [(2 - в²) / (а - в)]

To multiply fractions, we multiply the numerators and denominators:

[(2ав + 2в²) × (2 - в²)] / (в × (а - в))

Expanding the numerator:

(4ав - 2ав² + 4в² - 2в⁴) / (в × (а - в))

The expression (2а+2в / в) × (1 / а-в-1 / а+в) simplifies to:

(4ав - 2ав² + 4в² - 2в⁴) / (в × (а - в))

Please note that this simplified expression might still be further simplified depending on the context or specific requirements of the problem.