Question

3х(х+1)-2х(5х+3)=7х(2-х)+34

Answer 1

Ответ:

${3x}^{2} + 3x - {10x}^{2} - 6x = 14x - {7x}^{2} + 34 \\ { - 7x}^{2} - 3x = 14x - {7x}^{2} + 34 \\ { - 7x}^{2} - 3x - 14x + {7x}^{2} - 34 = 0 \\ - 17x = 34 \\ x = - 2$

Answer 2

To solve the given equation: 3x(x+1) - 2x(5x+3) = 7x(2-x) + 34, we can start by simplifying both sides of the equation and then solving for x.

Expanding the expressions on both sides: 3x(x+1) - 2x(5x+3) = 7x(2-x) + 34

Expanding the terms: 3x^2 + 3x - 10x^2 - 6x = 14x - 7x^2 + 34

Combining like terms: -7x^2 + 3x^2 + 3x - 14x - 6x - 34 = 0

Simplifying: -4x^2 - 17x - 34 = 0

To solve this quadratic equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = -4, b = -17, and c = -34. Substituting these values into the quadratic formula:

x = (-(-17) ± √((-17)^2 - 4(-4)(-34))) / (2(-4)) x = (17 ± √(289 - 544)) / (-8) x = (17 ± √(-255)) / (-8)

Since the discriminant (b^2 - 4ac) is negative, the quadratic equation has no real solutions. Therefore, the given equation has no solution.