Question

Lg(2x-1)=lg11-lg1,1​

Answer 1

Логарифмические уравнения.

Answer 2

To solve the equation, we'll start by simplifying the right side of the equation:

lg(2x-1) = lg11 - lg1.1

We know that lg(a) - lg(b) is equal to lg(a/b), so we can rewrite the equation as:

lg(2x-1) = lg(11/1.1)

Now, using the property that lg(a) = b is equivalent to 10^b = a, we can rewrite the equation again:

2x - 1 = 11/1.1

Simplifying the right side:

2x - 1 = 10

Adding 1 to both sides:

2x = 11

Dividing both sides by 2:

x = 11/2

Therefore, the solution to the equation lg(2x-1) = lg11 - lg1.1 is x = 11/2.