Question

Cos x +sin(p/2-x) +cos(p+x) =0

Answer 1

Ответ:

решение представлено на фото

Answer 2

To solve the equation cos(x) + sin(p/2 - x) + cos(p + x) = 0, we'll simplify and solve for x.

Let's start by simplifying the equation:

cos(x) + sin(p/2 - x) + cos(p + x) = 0

Using the trigonometric identity sin(A - B) = sin(A)cos(B) - cos(A)sin(B), we can rewrite sin(p/2 - x) as sin(p/2)cos(x) - cos(p/2)sin(x):

cos(x) + sin(p/2)cos(x) - cos(p/2)sin(x) + cos(p + x) = 0

Rearranging the terms:

cos(x) + cos(p + x) + sin(p/2)cos(x) - cos(p/2)sin(x) = 0

Now, let's combine like terms:

[1 + sin(p/2)]cos(x) + [1 - cos(p + x)] - cos(p/2)sin(x) = 0

At this point, it's difficult to find a general solution for x because the equation contains both sine and cosine terms. The solution will depend on the specific values of p and p/2.

If you provide specific values for p and p/2, I can try to find a solution for x using those values.