Question

(3x+7)*x+(4x-3)+(2x-2)+(x+1)+(2x-2)+(4x-3)*3

Answer 1

Объяснение:

1) Раскрыть модуль:

$3 {x}^{2} + 7x + 4x - 3 + 2x - 2 + x + 1 + 2x - 2 + 12x - 9$

2) Привести подобные члены. Вычислить:

$3 {x}^{2} + 28x - 15$

Answer 2

To simplify the expression, let's first combine like terms:

(3x+7)*x + (4x-3) + (2x-2) + (x+1) + (2x-2) + (4x-3)*3

Expand the terms that involve multiplication:

3x^2 + 7x + 4x - 3 + 2x - 2 + x + 1 + 2x - 2 + 12x - 9

Combine like terms:

3x^2 + (7x + 4x + 2x + x + 12x) + (-3 - 2 + 1 - 2 - 9)

Simplify the coefficients:

3x^2 + 26x - 15

So, the simplified expression is:

3x^2 + 26x - 15