Question

(a-7)(a+4)-(a+3)(a-10)

Answer 1

Ответ:

1)(а-7)(а+4)=а^2+4а-7а-28=а^2-3а-28

2)(а+3)(а-10)=а^2-10а+3а-30=а^2-7а-30

3)=1)-2)=-10а-58

-10а-58

-10а=58

а=-5,8

Answer 2

Ответ:

a² -3a -28 - a² +7a +30 = 4a+2

Answer 3

To simplify the expression, you can use the distributive property to expand both terms and then combine like terms. Let's go through the steps:

1. Expand the first term: (a-7)(a+4) = a(a) + a(4) - 7(a) - 7(4) = a^2 + 4a - 7a - 28 = a^2 - 3a - 28

2. Expand the second term: (a+3)(a-10) = a(a) + a(-10) + 3(a) + 3(-10) = a^2 - 10a + 3a - 30 = a^2 - 7a - 30

Now, combine the two expanded terms:

(a-7)(a+4) - (a+3)(a-10) = (a^2 - 3a - 28) - (a^2 - 7a - 30)

Now, distribute the negative sign to the terms inside the second parenthesis:

= a^2 - 3a - 28 - a^2 + 7a + 30

Next, combine like terms:

= (a^2 - a^2) + (-3a + 7a) + (-28 + 30) = 0a + 4a + 2 = 4a + 2

The simplified expression is 4a + 2.