Question

A) (a^-2b)^2 б) (-7x-1) ^2 в) (-5a+2b^4)^2 г) (x-12)(x+12) д) (-4n^3+7)(4n^3+7)

Answer 1

Держи решение! Надеюсь актуальное ещё

Answer 2

Sure, I'd be happy to help you with these expressions. It seems like you want to simplify each of these expressions. Let's go through them one by one:

A) $(a^{-2}b)^2$ To simplify this expression, you'll need to apply the exponent rules. When you raise a power to another power, you multiply the exponents: $(a^{-2}b)^2 = a^{-4}b^2$

Б) $(-7x - 1)^2$ To simplify this expression, you'll need to apply the square of a binomial formula, which is $(a - b)^2 = a^2 - 2ab + b^2$: $(-7x - 1)^2 = (-7x)^2 - 2(-7x)(1) + (-1)^2 = 49x^2 + 14x + 1$

В) $(-5a + 2b^4)^2$ To simplify this expression, you'll again use the square of a binomial formula: $(-5a + 2b^4)^2 = (-5a)^2 - 2(-5a)(2b^4) + (2b^4)^2 = 25a^2 - 20ab^4 + 4b^8$

Г) $(x - 12)(x + 12)$ To simplify this expression, you can use the difference of squares formula, which is $a^2 - b^2 = (a + b)(a - b)$: $(x - 12)(x + 12) = x^2 - 12^2 = x^2 - 144$

Д) $(-4n^3 + 7)(4n^3 + 7)$ This expression is also a difference of squares: $(-4n^3 + 7)(4n^3 + 7) = (4n^3)^2 - 7^2 = 16n^6 - 49$

So, the simplified forms of the given expressions are: A) $a^{-4}b^2$ Б) $49x^2 + 14x + 1$ В) $25a^2 - 20ab^4 + 4b^8$ Г) $x^2 - 144$ Д) $16n^6 - 49$