Question

Cos2x=0 срочнооооооооооооооо

Answer 1

Ответ:

Объяснение: косинус равен нулю в углах 90°(π/2) и 270°, 450° ( то есть 90°+180*n) (π/2+πn)

2х=π/2 + πn, где n∈Z( n принадлежит целым числам. Теперь все нужно разделить на 2

Тогда х= π/4 + (πn) /2, n∈Z

Answer 2

To solve the equation cos(2x) = 0, we need to find the values of x that satisfy the equation. Remember that the cosine function is zero at certain angles.

The general solution for cos(2x) = 0 is:

2x = π/2 + kπ or 2x = 3π/2 + kπ

where k is an integer.

Now, let's solve for x:

For the first case: 2x = π/2 + kπ Divide both sides by 2: x = (π/2 + kπ)/2 x = π/4 + kπ/2

For the second case: 2x = 3π/2 + kπ Divide both sides by 2: x = (3π/2 + kπ)/2 x = 3π/4 + kπ/2

So, the solutions for the equation cos(2x) = 0 are:

x = π/4 + kπ/2 or x = 3π/4 + kπ/2

where k is an integer, meaning there are infinite solutions for x that satisfy the given equation.