Question

Cosx ≤ -√ 2/2 срочно!!!

Answer 1

Объяснение:

Всё просто, переносим и по таблице смотрим значение косинуса

Answer 2

To solve the inequality $\cos(x) \leq -\frac{\sqrt{2}}{2}$, we first need to identify the values of $x$ that satisfy this inequality.

The given inequality $\cos(x) \leq -\frac{\sqrt{2}}{2}$ is true for $x$ values in the second and third quadrants of the unit circle.

In the second quadrant, the cosine function is negative, and in the third quadrant, it is also negative. The value $-\frac{\sqrt{2}}{2}$ is the cosine value of $45^\circ$ and $225^\circ$ (and their coterminal angles).

So, the solutions to the inequality are $x$ values such that:

$x = 180^\circ \pm \theta + 360^\circ \cdot n$

where $\theta = 45^\circ$ and $n$ is an integer.

Thus, the solutions are:

$x = 180^\circ + 45^\circ + 360^\circ \cdot n$ $x = 180^\circ - 45^\circ + 360^\circ \cdot n$

where $n$ is an integer. These are the general forms of solutions for $x$ in degrees. If you need a specific numerical solution, you can substitute different integer values for $n$ to get specific angles that satisfy the inequality.