Question

49x²-9=0 , (2x-7)²-7(7-4x)=0

Answer 1

Ответ:

см.в пр.файл

Объяснение:

ответ на листе

Answer 2

To solve the equations, let's take them one by one:

1. 49x² - 9 = 0

We can start by factoring the left-hand side of the equation:

49x² - 9 = (7x + 3)(7x - 3) = 0

Now, set each factor to zero and solve for x:

1. 7x + 3 = 0 7x = -3 x = -3/7

2. 7x - 3 = 0 7x = 3 x = 3/7

So, the solutions for the first equation are x = -3/7 and x = 3/7.

2. (2x - 7)² - 7(7 - 4x) = 0

Expand the left-hand side of the equation:

(2x - 7)(2x - 7) - 7(7 - 4x) = 4x² - 28x + 49 - 49 + 28x = 4x² = 0

Now, set 4x² to zero and solve for x:

4x² = 0 x² = 0 x = ±√0 x = 0

So, the solution for the second equation is x = 0.

In summary, the solutions for the equations are:

1. x = -3/7 and x = 3/7
2. x = 0