Question

X+3/4-x/2=3 не x и снизу 3/4 а x+3 и снизу 4

Answer 1

$\frac{x+3}{4}-\frac{x}{2}=3 \\ x+3-2x=12 \\ -x+3=12 \\ -x=12-3 \\ -x=9 \\ x=-9$

Answer 2

$\frac{x+3}{4}-\frac{x}{2} =3\\\\\frac{x+3-2x}{4} =\frac{12}{4} \\\\\frac{-x+3}{4} =\frac{12}{4} \\-x+3=12\\-x=9\\x=-9$

Answer 3

I apologize for any confusion. Based on your clarification, the equation you are referring to is:

(x + 3)/(4 - x/2) = 3

To solve this equation, we can follow these steps:

Step 1: Eliminate the denominator by multiplying both sides of the equation by (4 - x/2): (4 - x/2) * (x + 3)/(4 - x/2) = 3 * (4 - x/2)

The (4 - x/2) on the left side cancels out, leaving us with: x + 3 = 3 * (4 - x/2)

Step 2: Distribute 3 on the right side: x + 3 = 12 - (3/2)x

Step 3: Move all the x terms to one side and the constants to the other side: x + (3/2)x = 12 - 3

Step 4: Combine the x terms: (2/2)x + (3/2)x = 9/2 * x

Step 5: Simplify the right side: 9/2 * x = 9/2x

Step 6: Solve for x: x = (9/2) / (9/2) = 1

Therefore, the solution to the equation is x = 1.