Question

6(х+3)-2(у-4)=16-2х 10х-8=11-(12-5у

Answer 1

1) 6 ( x + 3) - 2( y - 4) = 16 -2x

6x + 18 - 2y + 8 = 16 -2x

8x - 2y = - 2

8x - 2y + 2 = 0

4x - y + 1 =0

2) 10x - 8 = 11- (12 - 5 y)

10x - 8 = 11 +12 + 5y

10x - 5y - 31 = 0

Answer 2

Объяснение:

1)6х+18-2у-8=16-2х

Answer 3

To solve the system of equations:

1. $6(x+3) - 2(y-4) = 16 - 2x$
2. $10x - 8 = 11 - (12 - 5y)$

Let's solve them step by step.

Equation 1:

Distribute the terms inside the parentheses: $6x + 18 - 2y + 8 = 16 - 2x$

Combine like terms: $6x - 2x + 18 + 8 - 2y = 16$ $4x + 26 - 2y = 16$

Subtract 26 from both sides: $4x - 2y = -10$

Divide by 2: $2x - y = -5$

Equation 2:

Simplify the right side: $10x - 8 = 11 - 12 + 5y$ $10x - 8 = -1 + 5y$

Add 8 to both sides: $10x = 7 + 5y$

Divide by 10: $x = \frac{7}{10} + \frac{1}{2}y$ $x = \frac{7}{10} + \frac{5}{10}y$ $x = \frac{7 + 5y}{10}$

Now we have two expressions for $x$ in terms of $y$: $2x - y = -5$ (Equation 1) $x = \frac{7 + 5y}{10}$ (Equation 2)

To find the values of $x$ and $y$ that satisfy both equations, we can substitute the expression for $x$ from Equation 2 into Equation 1:

$2 \cdot \frac{7 + 5y}{10} - y = -5$

Simplify: $\frac{14 + 10y}{10} - y = -5$ $14 + 10y - 10y = -50$ $14 = -5$

Since this is not possible, the system of equations is inconsistent and doesn't have a solution that satisfies both equations simultaneously. There might be a mistake in the original equations or some missing information. Please double-check the equations provided.