Question

(13z+1) (8z-7) (9z-17)=0

Answer 1

(13z+1) (8z-7) (9z-17)=0

Решим рассмотрев все возможные случаи.

1)

13z+1=0

13z=-1   |:13

z=-1/13

2)

8x-7=0

8z=7   |:8

z=7/8

3)

9z-17=0

9z=17    |:9

z=17/9

Ответ: $z_{1}=-\frac{1}{13} \;\;\;\;\;\;z_{2}=\frac{7}{8}\;\;\;\;\;\;z_{3}=\frac{17}{9}$

Answer 2

To find the solutions for the given equation, we need to set each factor equal to zero and solve for 'z'. So we have:

(13z + 1)(8z - 7)(9z - 17) = 0

Now, we can use the zero-product property, which states that if the product of two or more factors is equal to zero, then at least one of the factors must be equal to zero.

So, we set each factor to zero and solve for 'z':

1. 13z + 1 = 0 Subtract 1 from both sides: 13z = -1 Divide by 13: z = -1/13

2. 8z - 7 = 0 Add 7 to both sides: 8z = 7 Divide by 8: z = 7/8

3. 9z - 17 = 0 Add 17 to both sides: 9z = 17 Divide by 9: z = 17/9

So, the three solutions for the equation are: z = -1/13, z = 7/8, and z = 17/9.