Question

25a^2 + 15a = 21m2n^2 + 70mn^2 − 7n^2 = s^2 − 20s + 100 = 16k^2 − − ^2 = 2a^2 − 18 =

Answer 1

25a² + 15a = 5а(5а+3)

21m2n² + 70mn² − 7n² = 7n²(16m-1)

s² − 20s + 100 = (s-10)²

16k^2 − − ^2 = тут наверное что-то неправильно

2a^2 − 18 = 2(а²-9)= 2(а-3)(а+3)

Answer 2

To solve the given equations, let's take them one by one:

1. 25a^2 + 15a = 21m^2n^2 + 70mn^2 - 7n^2

This is an equation with two variables, 'a' and 'm'. To solve for 'a', we need more information or another equation.

2. s^2 - 20s + 100 = 0

This is a quadratic equation in 's'. We can solve it by factoring or using the quadratic formula.

Factorization: (s - 10)^2 = 0 s - 10 = 0 s = 10

Alternatively, using the quadratic formula: s = (-(-20) ± √((-20)^2 - 41100)) / (2*1) s = (20 ± √(400 - 400)) / 2 s = (20 ± √0) / 2 s = (20 ± 0) / 2 s = 20 / 2 s = 10

So, s = 10 is the solution to the equation.

3. 16k^2 - - ^2 = 0

It seems there is a formatting issue in the equation. The right-hand side of the equation appears to be missing. Please provide the complete equation, and I'll be happy to help you solve it.

4. 2a^2 - 18 = 0

This is also a quadratic equation in 'a'. Let's solve it:

2a^2 - 18 = 0

Divide the entire equation by 2 to simplify:

a^2 - 9 = 0

Factor the left-hand side:

(a + 3)(a - 3) = 0

Now set each factor to zero and solve for 'a':

a + 3 = 0 --> a = -3 a - 3 = 0 --> a = 3

So, the solutions for 'a' are a = -3 and a = 3.

Remember that if any of the equations in the first step are supposed to be equal to one another, please clarify that, and I can try to solve the entire system of equations for you.