Question

(х^2-9)^2-4(х^2-9)+3=0​

Answer 1

Вот смотри пожалуйста

Answer 2

To solve the equation (x^2 - 9)^2 - 4(x^2 - 9) + 3 = 0, we can use a variable substitution to simplify the equation. Let's substitute a new variable, u = (x^2 - 9), so the equation becomes:

u^2 - 4u + 3 = 0

Now, we can solve this quadratic equation for u. Factoring it, we have:

(u - 1)(u - 3) = 0

Setting each factor to zero, we get:

u - 1 = 0 -> u = 1 u - 3 = 0 -> u = 3

Since u = (x^2 - 9), we can substitute the values back:

x^2 - 9 = 1 -> x^2 = 10 -> x = ±√10 x^2 - 9 = 3 -> x^2 = 12 -> x = ±√12

Therefore, the solutions to the equation (x^2 - 9)^2 - 4(x^2 - 9) + 3 = 0 are: x = √10, -√10, √12, -√12.