Question

X^4-5x^2+4=0 СРОЧНО!!!!

Answer 1

Ответ:

На фотографии все подробно написано.

Answer 2

To solve the equation $x^4 - 5x^2 + 4 = 0$, we can use a substitution to simplify the equation. Let's set $y = x^2$, then the equation becomes $y^2 - 5y + 4 = 0$.

Now, we can solve this quadratic equation for $y$:

$y^2 - 5y + 4 = 0$

To factor this quadratic equation, we look for two numbers whose product is $4$ and whose sum is $-5$. Those numbers are $-1$ and $-4$:

$(y - 1)(y - 4) = 0$

Now, set each factor equal to zero and solve for $y$:

$y - 1 = 0 \Rightarrow y = 1$

$y - 4 = 0 \Rightarrow y = 4$

Since $y = x^2$, we can solve for $x$ by taking the square root of each value of $y$:

For $y = 1$, $x^2 = 1 \Rightarrow x = \pm 1$

For $y = 4$, $x^2 = 4 \Rightarrow x = \pm 2$

So, the solutions to the original equation are $x = \pm 1$ and $x = \pm 2$.