Question

5x2-6=(6x-5)(2x-3) алгебра​

Answer 1

Ответ:

5x2-6=(6x-5)(2x-3) алгебра​

Объяснение:

5x2-6=(6x-5)(2x-3)

10x-6=12x²-28x+15

ты не так записал, дальше идёт уравнение с двумя корнями

Answer 2

5*2-6=(6x-5)(2x-3)

4=12x^2-18x-10x+15

12x^2-28x+11=0

D=784-4*12*11=256

x1=28-16/24=0.5

x2=28+16/24=44/24=22/12=11/6=1 целая 5/6.

Answer 3

To verify whether the given equation is true, let's simplify both sides and see if they are equal:

Left-hand side (LHS): 5x^2 - 6

Right-hand side (RHS): (6x - 5)(2x - 3)

Expand the right-hand side using the FOIL method (First, Outer, Inner, Last):

(6x - 5)(2x - 3) = 6x * 2x + 6x * (-3) - 5 * 2x - 5 * (-3) = 12x^2 - 18x - 10x + 15 = 12x^2 - 28x + 15

Now compare the simplified right-hand side with the left-hand side:

LHS: 5x^2 - 6 RHS: 12x^2 - 28x + 15

The two sides are not equal. Therefore, the given equation 5x^2 - 6 = (6x - 5)(2x - 3) is not true.