Question

1. 2х – у = 2, 3х – 2у = 3 ; 2. х + у = 7, х – 3у = -5 ;

Answer 1

Ответ:

Объяснение:

1) у = 2х - 2

3х - 2 * (2х - 2) = 3

3х - 4х + 4 = 3

- х = -1

х = 1

у = 2 * 1 - 2 = 0

2) Методом вычитания:

х - х + у - ( - 3у) = 7 - (- 5)

у + 3у = 7 + 5

4у = 12 (: 4)

у = 3

х = 7 - у = 7 - 3 = 4

Answer 2

Объяснение:

2х-у=2. |-2

3х-2у=3

-4х+2у=-4

3х-2у=3

-х=-1

х=1

2-у=2

у=0

х+у=7. |-1

х-3у=-5

-х-у=-7

х-3у=-5

-4у=-12

у=3

х+3=7

х=4

Answer 3

It looks like you've provided two systems of linear equations. You can solve for the values of variables x and y using various methods such as substitution, elimination, or matrices. Let's solve both systems of equations step by step:

System 1:

1. $2x - y = 2$
2. $3x - 2y = 3$

We can use the first equation to express y in terms of x: $y = 2x - 2$

Substitute this value of y into the second equation: $3x - 2(2x - 2) = 3$ $3x - 4x + 4 = 3$ $-x + 4 = 3$ $-x = -1$ $x = 1$

Now that we have the value of x, substitute it back into the equation for y: $y = 2x - 2$ $y = 2(1) - 2$ $y = 0$

So, the solution to the first system is $x = 1$ and $y = 0$.

System 2:

1. $x + y = 7$
2. $x - 3y = -5$

You can use the first equation to express x in terms of y: $x = 7 - y$

Substitute this value of x into the second equation: $7 - y - 3y = -5$ $7 - 4y = -5$ $-4y = -12$ $y = 3$

Now that we have the value of y, substitute it back into the equation for x: $x = 7 - y$ $x = 7 - 3$ $x = 4$

So, the solution to the second system is $x = 4$ and $y = 3$.

To summarize:

1. First system solution: $x = 1$, $y = 0$
2. Second system solution: $x = 4$, $y = 3$